In a question, I am trying to find the first degree derivative of a vector
$r(t)= t^2\,\hat\imath - 2\cos\pi\,\hat\jmath$
Is this answer correct ?
answer : $r'(t) = 2t \,\hat\imath + 0 \,\hat\jmath$
I mean there is no t term in j vector,so shouldn't it be 0