"Derivative-like" Operator such that $H(f(x)^{g(x)}) = H(f(x))^{H(g(x))}$

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Given 2 functions $f(x),g(x)$ we have: $$D(f(x)+g(x)) = D(f(x))+D(g(x))$$ And $$D^*(f(x)g(x)) = D^*(f(x))D^*(g(x))$$ where $D^*$ is the multiplicative derivative: $$D^*(f(x)) = lim_{h\rightarrow 0} {\frac{f(x+h)}{f(x)}}^{1/h}$$

My question is whether there is another type of derivative $H$ such that $$H(f(x)^{g(x)}) = H(f(x))^{H(g(x))}$$