I have the following integral that represents the fluid's mass change in a tank with volume $V$ over time.$$\frac{d}{dt}\int_V\rho dV$$
- $\rho$ is the mass density of the fluid
- $dV$ is a differential volume within the tank
I know that
- the density can be treated as a continuous function within the tank, and
- that the volume of the tank is constant.
Based on #1$$\frac{d}{dt}\int_V\rho dV=\int_V\frac{d\rho}{dt}dV$$ Based on #2$$\int_V\frac{d\rho}{dt}dV=\frac{d\rho}{dt}V$$
How do I verify/explain the second step?