Derivative of Grassmann exponential

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Can anyone explain how to correctly carry out a derivative of a Grassmann exponential. Consider $e^{\theta}$ where $\theta$ is Grassmannian. Since, $\theta^2 = 0$ we have $$e^{\theta} = 1+\theta$$ And, hence, $$\frac{d}{d\theta}e^{\theta} = 1$$ which is obviously incorrect. Can someone please suggest the correct way to implement differentiation of a Grassmann exponential?