Derivative of $\left\lvert y \right\rvert $ = $x^2$ with respect to x.

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Pretty straight forward question that I need help with (This is part of a bigger question where |y|= $x^2$ is a curve, for which the tangent at a given point is to be found). Thanking you in advance.

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Hint: Rewrite $\left| y \right|$ as $\sqrt{y^2}$.