$A$ is a $2\times2$ matrix.
- $A$ is a symmetric matrix with the eigenvalues $\lambda_1$ and $\lambda_2$ (consider cases of all sign combinations).
- $A$ is skew–symmetric.
I think the vector field of symmetric matrix is an irrotational field and converges to the eigenvector if the eigenvalue is negative. The vector field of skew-symmetric matrix is a divergence-free field.
Hint: Note that the flows in this vector field are solutions to the system of linear differential equations $\frac{dx}{dt} = Ax$. It suffices then to consider the eigenvalues of the matrix $e^{At}$ (where $t > 0$).
Note that symmetric matrices have purely real eigenvalues, and skew-symmetric matrices have purely imaginary eigenvalues.