Let $$A = \{ x \in \Bbb C : x^6 =1 \}\;\; \text{and}\;\; B=\{ x^3 : x \in A \}$$
Describe $B$ and $|B|$
Is it $\{1\}$ or roots of $x$?
Thank you
Let $$A = \{ x \in \Bbb C : x^6 =1 \}\;\; \text{and}\;\; B=\{ x^3 : x \in A \}$$
Describe $B$ and $|B|$
Is it $\{1\}$ or roots of $x$?
Thank you
If you take the complex numbers ${\Bbb C}$ as underlying set, then $A$ is the set of 6th roots of unity: $$A = \{e^{2\pi i k/6}\mid k=0,\ldots,5\}.$$ Then $B$ is the set of 3rd powers of $A$, which are the 2nd roots of unity: $\pm 1$.