So I have the following exponential matrix.
$$e^{At} = \frac{1}{11}\begin{bmatrix}10+e^{11t} & -1+e^{11t} & -3+3e^{11t}\\-1+e^{11t} & 10+e^{11t} & -3+3e^{11t}\\ -3+3e^{11t} & -3+3e^{11t} & 2+9e^{11t}\end{bmatrix}$$
The determinant of this matrix is $0$, due to one of the eigenvalues being $0$. However, how can I see on the matrix that there is an eigenvalue that is $0$?