If A is an invertible matrix of order 2 , then det (A inverse) is equal to
A) det (A) B) 1 / (det A) C) 1 D) 0
I tried approaching this question am not getting it but I KNOW ONE THING YES (adj A) A = (det A)I maybe it can help...
If A is an invertible matrix of order 2 , then det (A inverse) is equal to
A) det (A) B) 1 / (det A) C) 1 D) 0
I tried approaching this question am not getting it but I KNOW ONE THING YES (adj A) A = (det A)I maybe it can help...
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Hint: $\det XY = \det X \det Y$, and $\det I = 1$.