I'm having trouble figuring out how I can solve this... I've never been good with formal proofs.
$$(\mathbb{R},\preceq), a\preceq b\iff a^{2}\leq b^{2}$$
I can easily see that it's Reflexive: $\forall a\in\mathbb{R}, a^{2}\leq a^{2}$
I'm not sure how to properly prove that it's transitive and anti-symmetric though. I get stuck here...
\begin{align} a\preceq b,\ b\preceq c&\Rightarrow a^{2}\leq b^{2},\ b^{2}\leq c^{2}\\ &\Rightarrow a^2+b^2\leq b^2+c^2 \end{align}
And then anti-symmetric:
\begin{align} a^2\leq b^2\wedge b^2\leq a^2&\Rightarrow a^2=b^2 ?? \end{align}
Can anybody give me any pointers on how to approach proving these things? Thanks.
Hint: If you got stuck it might be the time to look for a countable example. What can you say about the case where $a=-b$?