I am used to finding this by drawing the triangle and knowing the angle measurement. With the angle measurement i can find sin cos and tan. But i dont have angle all I have is line.
I have put a scan but only because I could not show the angle $a$ and $b$ Not because I am hoping you do my homework!! This is a test revision sheet not something I have to turn it. I am not good at using graph drawing software. That is the only reason I scanned my sheet.
My question is Number $6$ where you can see my work begun Consider line l containing points $O$ and $A$, and line $2$ the line containing points $O$ and $B$. Line $1$ is: $3x-2y=0$ determine the values of $A$) $\sin a$, $\cos a$, $\tan a$ Line $2$ is: $x-4y=0$ determine the values of $B$) $\sin b$, $\cos b$, $\tan b$
So my thought is to put it in Yintercept form and get the slope. I notice that both lines have no $y$ intercept and begin at origin.
line one has slope of $3/2$ line two has slope of $1/4$
I know that slope is rise/run or $\sin/\cos$ or $y/x$
NOW
HELP #1 With this information how do i find angle? I know atan converts ratio to angle, but this is a NON CALCULATOR SECTION.
HELP #2 And am i right to say that to find angle all i have to do is plug in the unit circle information for the sin and cos of that particular angle and solve?
You have SOH CAH TOA written on your paper, and you figured out (I think) that rise and run correspond to two sides of the triangle. Use the Pythagorean theorem to find the third, and you're set.