$((((/////$ & $*(((/// = **((//$
Where (, / and * are digits, & is some operation and = is equals, determine what base this statement is in, what operation & is and translate it to base 10.
From looking at it, the first number has 9 digits, second has 7 and the result has 6 digits. Lets say base is b.
This means the operation cannot be $ + $ or $\times$ as the result has a less digits than the other two numbers.
This also means the operation cannot be $-$ as the lower bound of the first number, $b^8$ minus the upper bound of the second number, $b^7-1$ is always going to be greater than the upper bound of the third number, $b^6-1$
In other words, $b^8-(b^7-1) > (b^6-1) \Leftrightarrow b^8 > b^7 +b^6-1$
This also means the operation cannot be $\div$ as the lower bound of the first number, $b^8$ divided by the upper bound of the second number, $b^7-1$ is always going to be smaller than the upper bound of the third number, $b^6-1$
In other words, $\frac{b^8}{b^7-1} <b^6-1 \Leftrightarrow b^8<b^{13}-b^7-b^6+1$
Therefore, one of the only viable operations left is the modulo. However, I have no idea how to continue this.
UPDATE: question is wrong, ill edit in the right question when i get to it.