I want to determine the present value of a perpetual annuity, which will incur an interest payment of € 1 at the end of each year;
A calculative interest rate $r$ is assumed.
We are at the time $t = 0$, the first payout is in $t = 1$.
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Could you maybe give me a hint about how we could calculate it?
Is it maybe $1+r\cdot t$ ?
Let denote the annuity denote as $a$ and the interest rate as $r$. If the annuity incur an interest of 1€ per year then $a\cdot r=1$.
You receive an amount of a€ for $n$ periods. The present value of that payments is
$PV=\frac{a}{q^n}\cdot \sum_{i=0}^{n-1} q^i=\frac{a}{q^n}\cdot \frac{1-q^n}{1-q} \quad$ with $q=1+r$
$=\frac{a}{q^n}\cdot \frac{1}{1-q}-\frac{a}{q^n}\cdot \frac{q^n}{1-q} =\frac{a}{q^n}\cdot \frac{1}{1-q}- \frac{a}{1-q}= \frac{a}{q^n}\cdot \frac{1}{1-q}+ \frac{a}{q-1}$
Now $n$ goes to infinity.
$$\lim_{n\to \infty } \frac{a}{q^n}\cdot \frac{1}{1-q}+\lim_{n\to \infty }\frac{a}{q-1} $$
$=0+\frac{a}{q-1}$
with $q=1+r$ we get
$PV=\frac{a}{1+r-1}=\frac{a}r$
With $a\cdot r=1$
$PV=a^2$ or $PV=\frac1{r^2}$