Initially, I thought that calculating$$\int_\gamma \frac{\zeta(z)}{(z-1)^n}dz$$ directly, where $n \in \mathbb{Z}$ and $\gamma$ is an anticlockwise contour around $z=1$ with winding number $1$, would be a nice way of doing this, but I think this is impossible. Is there a nice way of showing that $$\zeta(s)=\frac{1}{s-1}+\sum_{n \ge 1}\frac{(-1)^n}{n!}\lim_{m \to \infty}\sum_{j=1}^m\frac{\log j^n}{j}- \frac{\log j^{n+1}}{n_1}?$$
2026-03-30 03:55:21.1774842921
Different methods of calculating $\zeta(s)$'s Laurent series.
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