Differentiability at a point of a cuve

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I have to study the differentiability of the following curve $$\begin{array}{cccc} C: & [0, 2\pi ]& \longrightarrow & \mathbb{C} \\ & t & \longmapsto & r(t+i-ie^{-ti}) \end{array}$$ at the points $t=0$ and $t=2\pi$.
Differentiating we obtain that $$\begin{array}{cccc} C': & \mathbb{R} & \longrightarrow & \mathbb{C} \\ & t & \longmapsto &r\left( 1-e^{-ti}\right) \end{array}$$

My question is the following: is it enough to say that since $$C^\prime (0)=0 $$ $$ C^\prime (2\pi)=0$$ the tangent vector is not well-defined, therefore the curve is not differentiable?
If not, could anyone point me how to do it properly?