Differentiation of a summation function. Please advise

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Please help me understand the differentiation of this function.

$$P_L = \sum_{i=1}^{n_g}\sum_{j=1}^{n_g} P_iB_{ij}P_j~+~\sum_{i=1}^{n_g}B_{0i}P_i~+~B_{00}$$

What would the partial differentiation $\frac{\partial P_L}{\partial P_i}$ be?

My understanding is that it should be

$$\frac{\partial P_L}{\partial P_i} = \sum_{i=1}^{n_g}\sum_{j=1}^{n_g} B_{ij}P_j~+~\sum_{i=1}^{n_g}B_{0i}$$

However, the book says

$$\frac{\partial P_L}{\partial P_i} = 2\sum_{j=1}^{n_g} B_{ij}P_j~+~B_{0i}$$

What am I missing please?

Any help would be appreciated. Thanks