Differentiation with polar coordinates

425 Views Asked by At

enter image description here

I'm sorry if this is supposed to be something basic but I'm not being able to understand if r is as given above, how have they worked out r dot? What have they differentiated the x,y and z coordinates with respect to? r dot means r differentiated with respect to what?

Any help would be much appreciated.

2

There are 2 best solutions below

0
On BEST ANSWER

Concentrate first on the $x$ parameterisation. Write $$x(r(t), \theta(t)) = r(t) \cos (\theta(t))$$

Remember that the product rule for differentiation is $$\frac{d}{dt}(uv) = u\frac{dv}{dt}+v\frac{du}{dt}$$ Hence \begin{align} \frac{dx}{dt} &= \dot{x} \\ &= \frac{d}{dt}(r \cos \theta ) \\ &= \frac{dr}{dt}\cos \theta + r \frac{d}{dt}\cos \theta \\ &= \frac{dr}{dt}\cos \theta - r \sin \theta \frac{d \theta}{dt} \\ &= \dot{r}\cos \theta - r \dot{\theta} \sin \theta \end{align} And the remaining two derivatives can be found similarly.

0
On

It seems that $\underline {r}$ is a vector in the $x-y$ plane expressed in polar coordinates with $r$ and $\theta$ depending on a same parameter $t$ (it can be the time). The notation $\dot r$ and $\dot \theta$ are used to indicate the derivative with respect the parameter $t$ and the chain rule is applied to the components of the vector.