If m is a power of $3$, n is a power of $3$, prove that $m+n$ is never a power of $3$.
This is the question that I was given, unfortunately, my teacher doesn't like to teach and I' left reading a $1000$ page book by myself answering these random questions that aren't covered in our book.
Edit: I think I really need help defining what is meant by a power of $3$. When they say $m$ is a power of $3$ does that mean $m=3\enspace\text{or}\enspace A^m = \enspace\text{or}\enspace A^3$ ?
if so $A^m + B^n$ with $m$ & $n$ being powers of $3 == A^3 + B^3$ and therefore $m+n = 3+3 = 6$ and a power of $6$ is not a power of $3$ ?
Given $m=3^x$ and $n=3^y$, assume $m+n=3^x+3^y=3^z$. Note that any power of $3$ is an odd number. An odd number plus an odd number cannot equal an odd number. Hence, you have a proof by contradiction. I leave it to you to show that powers of $3$ are odd.