I have the following parametric equation:
$x = 24 \sin (2πt), y = -24 \cos(2πt) + 35$
This parametric equation is related to a diagram of a Ferris wheel, and is the equation of motion of a point $A$ on the diagram which is attached. Ferris Wheel Diagram
I need to find the cartesian equation of the path of $A$, since the original equation given on the diagram is a parametric equation and find the distance between $O$ and $A$ when $t=0.25$.
I have found the cartesian equation and it is here, but I don't know how to find the distance between $O$ and $A$ on the diagram ($A$ is one of the smaller double Ferris wheel). Do I assume that since $O$ is stationary it is on the origin of the plane, and I just work out how far away from the origin is $A$ at $t=0.25$, or am I just approaching this wrong? It has been a long time since I have done vectors, so I am sorry if I sound completely wrong. Has the distance formula got anything to do with it?
Then next I have to state the position vector of point B at time $t$ minutes. I have no idea how to approach this, so this will be of additional help.
Correct me if I am wrong in my thinking somewhere.
Extra information: The radii of $A$ and $B$ are the same and the distance between $AX$ and $BX$ is the same so they are equidistant.