$$\log_{27}x = 1 - \log_{27}(x-0.4)$$
$$\log_{27}(x(x-0.4))=1$$ $$x=5.4,\, x=-5$$
I'm confused on the second line. How come it is not $\log_{27}(x+x-0.4)$?
$$\log_{27}x = 1 - \log_{27}(x-0.4)$$
$$\log_{27}(x(x-0.4))=1$$ $$x=5.4,\, x=-5$$
I'm confused on the second line. How come it is not $\log_{27}(x+x-0.4)$?
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$\log(a)+\log(b)=\log(ab)$ where $\log(x)$ is the logarithm in any base.