Divergence theorem given $\overset{\rightharpoonup} F = x \hat{i} + y \hat{j} +z \hat{k}$ and the volume

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I am trying to calculate $\iint\limits_S \overset{\rightharpoonup} F \cdot \overset{\rightharpoonup} n\ dS$ using the divergence theorem.

It is given that $\overset{\rightharpoonup} F = x \hat{i} + y \hat{j} +z \hat{k}$ and $V$ is a 3-dimensional object having volume $4$ bounded by the surface $S$.

Here are the steps I have taken:

Divergence theorem

$$\iint\limits_S \overset{\rightharpoonup} F \cdot \overset{\rightharpoonup} n\ dS = \iiint\limits_V \text{div} \overset{\rightharpoonup} F dx\ dy\ dz$$

Find the divergence of $\overset{\rightharpoonup} F$

$$\text{div} \overset{\rightharpoonup} F = \frac{\partial}{\partial x}x + \frac{\partial}{\partial y}y + \frac{\partial}{\partial z}z = 3$$

Substitute into the divergence theorem

$$\iiint\limits_V (3)\ dx\ dy\ dz$$

$$3 \cdot \iiint\limits_V\ dx\ dy\ dz$$

Given the volume is 4,

$$\iint\limits_S \overset{\rightharpoonup} F \cdot \overset{\rightharpoonup} n\ dS = 3 \cdot 4 = 12$$

Is this correct?

My main doubt is whether it is permissible to replace $\iiint\limits_V\ dx\ dy\ dz$ with $4$ in the last step.