Do covariant functors preserve direct sums?

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Suppose $T$ is a covariant functor from the category $R$-mod to Ab (the category of abelian groups)

Is is necessary that $T(B \oplus C) \cong T(B) \oplus T(C) $ ?

Does the answer change if we assume that the functor is left exact ?

I am trying to prove that left exact covariant preserves pullbacks and need this there. Thanks

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In an additive category (in particular abelian), direct sums can be characterized by the existence of certain morphisms. So, if $A$ and $B$ are objects in the additive category and $C$ is another object, then $C$ is the coproduct and the product of $A$ and $B$ if and only if there are morphisms \begin{align} i_A\colon A&\to C\\ i_B\colon B&\to C\\ p_A\colon C&\to A\\ p_B\colon C&\to B \end{align} such that $$ p_Ai_A=1_A,\quad p_Bi_B=1_B,\quad i_Ap_A+i_Bp_B=1_C $$ Therefore, any additive functor preserves finite coproducts (and products, since they coincide).

Also, a functor between additive categories is additive if and only if it preserves finite coproducts. See Mac Lane's “Categories for the working mathematician”.