Does any discrete signal has z-transform (even noise)?

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I faced to the following discrete

$$ y[n+1]=Ay[n]+Bx[n]+\eta[n] $$

where $y[n] \in \mathbb{R}^n$, $A$ and $B$ are matrices with appropriate dimension, and $\eta[n]$ is noise.

I have no problem with the following

$$ y[n+1]=Ay[n]+Bx[n] $$

Because I can write the z-transform as follows

$$ zY(z)-zY(0)=AY(z)+BX(z) $$

Can I simply write the following even for noise?

$$ zY(z)-zy(0)=AY(z)+BX(z)+ H(z) $$

Please answer it conceptually and explain it.