Does every knot have a diagram such that every arc is a bridge?

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Since the number of crossings in a knot diagram is the same as the number of arcs (or edges), can you construct a diagram of a knot where each arc crosses over exactly one other arc? My first thought would be to prove or disprove this with Reidermeister moves, but I couldn’t seem to find a way to make an argument because the 2nd and 3rd moves make things much more complicated.

Is there a way to prove or disprove this?