S. Colley, Vector Calculus, p.246 writes:
but isn't $\cos$ an even function? I am baffled. Can you please explain?
2026-04-27 18:31:25.1777314685
Does every Taylor series for $\cos$ only have even exponents?
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It will have only even exponents e.g. if you write the Taylor series around the point $x_0 = 0$. So there's no contradiction here. We're around a different point here $x_0 = \pi / 2$.