Suppose I have the set of all things $\{a, b, c,... \}$. It seems to me that $ \mathcal P \{a, b, c,... \} $ would be the set of all sets, which sounds like it includes the set of all sets that do not contain themselves. However, I can't envision deriving that set from the power set of $\{a, b, c,... \}$.
My thinking is that, so long as there are no sets in $\{a, b, c,... \}$, then the paradox doesn't arise. Otherwise, my reasoning, or my knowledge, is shamefully off.
Where did I go wrong?
It's not clear at all what you mean by "thing". Is the number $4$ a thing? What about the ordered pair $(5, 2)$? Or $\mathbb N$? Some of those may seem to you to be more or less like "things" than others, but in modern mathematics they are all regarded as sets. It sounds like you want to craft a variation of set theory that has both a rigidly-enforced distinction between "things" and "sets of things", and such a theory can be crafted -- see http://en.wikipedia.org/wiki/Urelement. The "things" in such a theory are often called "atomic elements" or "atoms", for natural reasons.
But in fact it turns out that "things" are entirely unnecessary. We can do just fine without them! In standard set theory we begin with the empty set $\varnothing$, start creating power sets, and are able to build up everything we need for mathematics. Ironically, though, in a theory that has no "things" in it, the "set of all things" is the empty set!
As for Russell's Paradox, it arises as soon as you start talking about "the set of all sets." If there were a set of all sets, then you would consider the subset of all sets that do not contain themselves, and that leads to a paradox. So in any version of set theory, whether there are atomic elements or not, there is no set of all sets.