I saw many functions on my book and all of the tangent line of inflection point always pass through the curve, Here are examples :
Example 1 :
$$f(x) = x^3 \quad (x=0)$$
Tangent line at $x = 0$, $l:y=0$
Then we know that $l$ passes through the $f(x)$.
Example 2 : $$f(x)=\sin x\quad (x=0)$$
Tangent line at $x = 0$, $l: y = x$
We know $l$ passes through the $f(x)$.
I got a curiosity about this, so my question is :
Let $f$ is differentiable function and $f$ is not a constant, linear function.
If a line $l$ is a tangent line of inflection point, $l$ passes through $f$ near of inflection point?
I think this is true, but I have no idea to prove this. Thanks for help.
Another way to show this is
Let $l(x)$ to be the tangent line of $f(x)$ at $x=a$.
Case-$1$: $f''(x<a)<0<f''(x>a)$, $$f'(x<a) < f'(a) < f'(x>a)$$
$$x<a:\quad l(x)=f(a)+\int_a^xf'(a)\,dt \,\,>\,\, f(a)+\int_a^xf'(t)\,dt=f(x)$$ $$x>a:\quad l(x)=f(a)+\int_a^xf'(a)\,dt \,\,<\,\, f(a)+\int_a^xf'(t)\,dt=f(x)$$
Case-$2$: $f''(x<a)>0>f''(x>a)$, $$f'(x<a) > f'(a) > f'(x>a)$$
$$x<a:\quad l(x)=f(a)+\int_a^xf'(a)\,dt \,\,<\,\, f(a)+\int_a^xf'(t)\,dt=f(x)$$ $$x>a:\quad l(x)=f(a)+\int_a^xf'(a)\,dt \,\,>\,\, f(a)+\int_a^xf'(t)\,dt=f(x)$$
So $l(x)$ passes through $f(x)$.