$$∫ \dfrac{1}{ax+b} dx = \dfrac{1}{a}\log_{e}{|ax+b|} + c$$
but if you factor out $1/a$ from the integral first then the anti derivative becomes
$$\cfrac{1}{a}\log_{e}\left|x+\dfrac{b}{a}\right| + c$$
which is correct? If both why?
$$∫ \dfrac{1}{ax+b} dx = \dfrac{1}{a}\log_{e}{|ax+b|} + c$$
but if you factor out $1/a$ from the integral first then the anti derivative becomes
$$\cfrac{1}{a}\log_{e}\left|x+\dfrac{b}{a}\right| + c$$
which is correct? If both why?
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