Does this equation $$e^{2x\pi}= \frac{1+x}{1-x}$$ has any solution for $x\in(0,1)$
i have tried to differenciate the function $f(x)= e^{2x\pi}- \frac{1+x}{1-x}$ and tried to check whether it is increasing or decreasing . but this donot help. Any suggestion please.
Note that $\lim_{x\to1}e^{2\pi x}\frac{1-x}{1+x}=0$ and that $e^{2\pi x}\frac{1-x}{1+x}>1$ when $x=\frac12$. But then $e^{2\pi x}\frac{1-x}{1+x}=1$ for some $x\in(0,1)$, which means that, for such a number $x$, $e^{2\pi x}=\frac{1+x}{1-x}$.