I asked a question earlier and got the solution
https://gyazo.com/372f0352b7d8aeb180586ac5218dd1bc
I understand it all apart from this part
AB(C⊕D)+D′(AB′+A′B)
How can you use D′(AB′+A′B) if D is already used in AB(C⊕D)
I might just be being really silly and missing something haha but I cant figure it out after looking at it for 10 minutes
I'll do my best to illustrate what's happened here:
$$ A'BC'D' + AB'C'D' + AB'CD' + ABC'D + ABCD' \\ = A'BC'D' + (AB'C'D' + AB'CD') + (ABC'D + ABCD') \\ = A'BC'D' + (AB'D'(C')+AB'D'(C)) + (AB(C'D)+AB(CD')) \\ = A'BC'D' + AB'D'(C'+C) + AB(C'D+CD') \\ = A'BC'D' + AB'D'(1) + AB(C \oplus D) \\ = A'BC'D' + AB'D' + AB(C \oplus D) \\ = D'(A'BC' + AB') + AB(C \oplus D) $$
I think the solution includes an oversight by disregarding the $C'$ in the first term.