Suppose $\hat{x}^\top \hat{y} = 1 + \mathcal{O}(\delta^2)$ as $\delta\to0$, where $\hat{x}$ and $\hat{y}$ are unit vectors. Can I say that for $\hat{z}\perp \hat{x}$ we then have $\hat{z}^\top \hat{y} = 0 + \mathcal{O}(\delta^2)$?
2026-04-24 13:44:52.1777038292
Dot product of almost perpendicular vectors
111 Views Asked by user318854 https://math.techqa.club/user/user318854/detail AtRelated Questions in REAL-ANALYSIS
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