I understand everything except 2 doubt
1) Why u is measurable
2) why $u\chi_n\in L^2(\Sigma)$
I have highlighted text.
Any Help will be appreciated
I understand everything except 2 doubt
1) Why u is measurable
2) why $u\chi_n\in L^2(\Sigma)$
I have highlighted text.
Any Help will be appreciated
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Quotient of two measurable functions is still measurable, this follows by the composition of the continuity map $(u,v)\rightarrow u/v$ and $x\rightarrow(f(x),g(x))$ for measurable functions $f,g$.
On the set $\Omega_{n}$, $\theta^{-1}\leq\epsilon_{n}^{-1}$, so $\|u\chi_{\Omega_{n}}\|_{L^{2}}\leq\epsilon_{n}^{-1/2}\|v\|_{L^{2}}$.