Drawing the subgroup lattice of D10

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I've been tasked with drawing a subgroup lattice of the dihedral group of order 10. I know from Lagrange's theorem that non-trivial subgroups must have order 2 or 5. Finding the subgroups of order 2 is straightforward, since there can be only one element besides the identity, but what about the groups of order 5? I could feasibly brute-force my way through this problem by going through the elements of $D_{10}$ one by one and trying to construct groups of order 5, but there must be a better way to solve this.

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As $5$ is a prime number, groups of order $5$ are cyclic. So you should find all the elements of order $5$ in $D_{10}$ and then determine what subgroups they generate.

Note that any non-identity element of a cyclic group of order $5$ generates that group. So if an element of order $5$ is contained in a subgroup that you have already found, then it generates that subgroup and you do not need to check it again.