Prove or disprove: If $H$ is normal in $G$ and $H$ and $G/H$ are abelian, then $G$ is abelian.

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My counterexample I wanted to try is $D_{8}$ and its center $Z(D_{8})$. However, is $Z(D_{8})$ abelian? I am guessing it is because it is cyclic? I am not very knowledgeable with dihedral groups.