Let $R$ be a ring with $1$ and $M$ be an $R$-module. With nice enough conditions, we can define
- $\operatorname{Rad}(M) = \text{(unique) smallest submodule $N$ of $M$ such that $M/N$ is semisimple}$
- $\operatorname{Soc}(M) = \text{(unique) largest semisimple submodule $N$ of $M$}$
So $\operatorname{Rad}(M)$ is dual to $\operatorname{Soc}(M)$.
My question: What does it mean to be dual in this case? These conditions do feel dual but how do we formalize this duality notion?
Here's a somewhat late answer, in case you're still wondering.
TL;DR: When dealing with the poset of submodules of $M$, we have that intersections of submodules are dual to sums of submodules, and maximal submodules are dual to simple submodules.
Longer answer:
The core idea here is that the radical of a module $M$ is not dual to the socle of $M$ in the category $\operatorname{Mod}R$; instead, these concepts are dual in the poset category of submodules of $M$. Let $X$ denote the poset of submodules of $M$ ordered by inclusion, and let $\mathcal{C}_X$ denote its poset category.
To see how the radical and socle are dual, recall that the radical of $M$ is the intersection of all maximal submodules of $M$. We can phrase this in categorical terms:
Thus the radical of $M$ is the product of all penultimate objects in $\mathcal{C}_X$. We can now find the dual concept in the category $\mathcal{C}_X$: the "co-radical" of $M$ is the coproduct of all co-penultimate objects in $\mathcal{C}_X$. Let's unpack what this means:
Thus the "co-radical" of $M$ is the sum of all its simple submodules. But this is the socle of $M$! So we see that the radical and socle of $M$ are dual in the poset category $\mathcal{C}_X$.