$e^{17 + ln(7x)}$ - I'm stuck on this problem. I could really use some help

Question

I know that the $\ln{(7x)}$ will go to just $7x$, but I'm confused about how the $17$ fits into the answer.

Answer 1

I assume you mean $e^{17+\ln(7x)}$ and you want to simplify?

You can use the following:

$e^{a+b} = e^ae^b$

$e^{\ln(x)}=x$

Answer 2

$$e^{17+\ln 7x} = e^{17} e^{ \ln 7x} = 7xe^{17}$$

And it does not simplify any more.