Easy question about sup norm

152 Views Asked by At

Im reading through terence tao's Analysis2 book and came across the following page describing the sup norm metric.

enter image description here

I dont understand the example at the end. The difference $|x_i - y_i|$ refers to the $i$-th index of in this case $(1,6)$ and $(4,2)$. Why does this not result in the $sup(|1-4|=3,|6-2|=4)$. And second, why in the example is the supremum of (5,2) equal to 7 instead of the maximum of the numbers 5 and 2, which would be 5?

2

There are 2 best solutions below

1
On BEST ANSWER

Yes, this is clearly a mistake. The first one is taking $d_{l^\infty}((1,4), (6,2) = \max\{5,2\}$ instead of $d_{l^\infty}((1,6), (4,2) = \max\{3,4\}$ and the second one is not actually taking the Maximum, but the sum, which would be the $l_1$ norm.

I guess they wanted to give an example of a different norm than the euclidian norm, but they mixed up $l_1$ and $l_\infty$ in the process.

0
On

Your are right, this is an error. Instead it should be $$ d_{l^\infty}((1,6),(4,2))=\sup\{3,4\}=4. $$ This error has already been recorded in the list of errata, which you can find here: https://terrytao.wordpress.com/books/analysis-ii/