"Easy" triangle problem (hight school)

Question

Can someone give me a hint to this "easy" problem? In the triangle ABC, we have: DE || BC, FE||DC, AF=1, FD=2, find DB=?

Answer 1

1) $$FE||DC \Rightarrow\frac{AF}{FD}=\frac{AE}{EC}=\frac{1}{2}$$ 2) $$\frac{AD}{DB}=\frac{AE}{EC}=\frac{1}{2}$$ Hence, $BD=2AD=6$