Let's say $A$ is a normal matrix, that is, $AA^*=A^*A$ - then what can be said about the eigen-pairs of $A$ and $A^*$?
I'm trying to show that if $Ax = kx$, then $A^*x = \overline{k}x$. How do I proceed?
I tried the following:
- $Ax = kx$ implies
- $x^*A^* = \overline{k}x^*$
- Multiplying by $Ax$ on both sides and replacing $A^*A$ by $AA^*$ - but couldn't get anywhere past this.
Could someone point me in the right direction? Any help is appreciated.
Hint: We have $\|Ax-kx\|^2 =\|A^*x-\bar kx\|^2$.