Let $A \in \mathrm{R}^{n\times m}$ be a matrix of rank $n$ (with $m>n$). Let $A^+$ be the Moore-Penrose pseudoinverse of $A$. The matrix
$$ A^+ A = A^T(A A^T)^{-1} A $$
has eigenvalues $\lambda_i \in \{0,1 \}$. How can I proof this?
2026-03-28 07:25:22.1774682722
Eigenvalues of $A^+ A$
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