Eigenvectors of the derivative operator are the exponential function

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The eigenvectors of the derivative operator are the exponential function. The derivative operator is not Hermitian, so we get complex eigenvalues.

$\frac{d}{dx} f(x) = \lambda f(x) \Rightarrow f(x)=Ce^{\lambda x}$

what is the solution of the eigenvalue problem: $e^{zcos(x)}$

$\frac{d}{dx} e^{zcosx} = -ze^{zcosx}sin(x)$

$-\frac{1}{sinx}\frac{d}{dx} e^{zcosx} = ze^{zcosx}$

seeking for the eigenvectors. I don't see the solution.

I am very lost. Thank you.