Hi I've read the proof here.
https://proofwiki.org/wiki/Eisenstein%27s_Lemma
On the line about division it says
$$k a = p \times \left \lfloor {\dfrac {k a} p} \right \rfloor + r$$ where $r\in S′$.
Can someone explain why $r\in S′$?
Thanks
Hi I've read the proof here.
https://proofwiki.org/wiki/Eisenstein%27s_Lemma
On the line about division it says
$$k a = p \times \left \lfloor {\dfrac {k a} p} \right \rfloor + r$$ where $r\in S′$.
Can someone explain why $r\in S′$?
Thanks
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This is due to the division algorithm as shown in the comments.