$f(x,y) = \begin{cases} x^2/y & y \neq 0 \\ 0 & y = 0\end{cases}$
I need to draw the elevation (or you may call it Equivalent curve) of this function and I don't know how to draw them. Can some-one help me please? Thanks a lot.
2026-03-30 10:15:27.1774865727
Elevation of 3D function
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Set $f(x,y)=k$ for some constant $k$ then $y=\frac{1}{k}x^2$. In other words the contour lines (the lines with constant $f$ values) will consist of a series of quadratic curves emanating from the origin in both the positive-$y$ and negative-$y$ directions.
Begin with $k=\pm1$ and so draw $y=\pm x^2$. And then consider $k=\pm 2$ and you know this is equal to the curves you've already drawn but divided by 2, and so on for increasing $k$. Like this: