Embedding partially ordered spaces in a product of chains

83 Views Asked by At

I've been thinking about the following construction recently and was wondering whether it is something used in the literature, and whether it is cannonical? As the title suggests, it is a way to embed a partial order in a product of totally ordered spaces.

Let $P$ be a partially ordered space, and $\mathcal{C}(P)$ be the collection of chains over $P$. Then we can embed $\mathfrak{e}:P\to \underset{C\in \mathcal{C}(P)}{\times}C$ by the following definition:

If $p\in C$, then $\mathfrak{e}$ maps to an element whose $C$-th coordinate is $p$. Moreover for all $C\in \mathcal{C}(P)$ choose an arbitrary element $e_C\in P$, and if $p\notin C$ define the $C$-th coordinate of $\mathfrak{e}(p)$ to be $e_C$. More specifically

$$ \Big[\mathfrak{e}(p) \Big](C)= \begin{cases} p & ,p\in C\\ e_C &, p\notin C \end{cases} $$

In the case where there are maximal chains, we can consider instead of $\mathcal{C}(P)$ an alternative collection $\tilde{\mathcal{C}}(P)$, where if $C'$ is a maximal chain on $P$, then we omit all chains contained in $C'$ from $\tilde{\mathcal{C}}(P)$.

Is this sort of construction standard? Is there perhaps a better procedure known in the literature?

1

There are 1 best solutions below

0
On

Just to give closure to the question, the most relevant notion for my question that I was able to find, is the one used in defining the Order dimension of a poset.