What is
$$\int \ln (0.25+ x^2) \mathrm{d}x ?$$ Too bad am not yet very familiar with Wolfram Alpha.
Hint:$$\int1.\log\left(\frac14+x^2\right)\,\mathrm dx=x\log\left(\frac14+x^2\right)-\int\frac{2x^2}{\frac14+x^2}\,\mathrm dx.$$
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Hint:$$\int1.\log\left(\frac14+x^2\right)\,\mathrm dx=x\log\left(\frac14+x^2\right)-\int\frac{2x^2}{\frac14+x^2}\,\mathrm dx.$$