I'm trying to prove the following limit:
$$\lim _{x\to 3}\frac{18}{x^2}=2$$
I'm not seeing how I can relate δ with ε, here's what I have done:$$\left|\frac{18}{x^2}-2\right|=\left|\frac{18-2x^2}{x^2}\right|=2\left|\frac{9-x^2}{x^2}\right|=2\frac{\left|x+3\right|}{\left|x^2\right|}\left|x-3\right|$$
I'm not sure how to continue to relate $\delta$ with $\varepsilon$ .