Is it the following allowed using Parseval's theorem?
$$\int_{\infty}^{\infty} g(k) f(x)^2 dx = \frac{1}{2\pi}\int_{\infty}^{\infty} g(k) F(k)^2 dk$$
with $F(k)$ the Fourier transform of $f(x)$.
Is it the following allowed using Parseval's theorem?
$$\int_{\infty}^{\infty} g(k) f(x)^2 dx = \frac{1}{2\pi}\int_{\infty}^{\infty} g(k) F(k)^2 dk$$
with $F(k)$ the Fourier transform of $f(x)$.
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