Equation $\frac{1}{a_1}+\ldots +\frac{1}{a_{2018}} = 1$

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Let $A_{n}=\{(a_1,a_2,\ldots,a_{n}): a_i\in\mathbb{Z_{>0}}|\ \ \frac{1}{a_1}+\ldots \frac{1}{a_{n}} = 1\}$.

My question. What is $|A_n|\operatorname{mod}2$, for $n=2018$? That is what is the parity of cardinality of $A_n$, for $n=2018$.

I can solve this problem for numbers of the type $n=2^i+2^k$. But in the case $n=2018$ I find it more interesting.

Also I'm interesting where such equations can arise.