The problem is to solve $3^x+4^x+14^x=10^x+11^x$ for $x>0$.
I have noticed that $x=1$ and $x=2$ are solutions; probably they are the only solutions, but I do not know how to prove it; I have tried some monotony and convexity arguments.
2026-04-07 02:07:16.1775527636
Equation involving exponentials $3^x+4^x+14^x=10^x+11^x$
119 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in EXPONENTIAL-FUNCTION
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