I went about this one the same as the last two problems like it I did and came up with:
$$\langle1,1,1\rangle*\langle x-1,y-1/2,z-1/3\rangle$$ $$(x-1)+(y-1/2)+(z-1/2)=0$$ $$x+y+z = 11/8$$
But the answer is
$$6x+6y+6z = 11$$
So I'm way off aside from having an 11....